Insert BS here A place to discuss anything you want!

Physics Help

Thread Tools
 
Search this Thread
 
Old 04-17-2004, 10:58 PM
  #1  
Senior Member
Thread Starter
 
CGeek2k's Avatar
 
Join Date: Nov 2003
Location: Hell (Colorado School of Mines)
Posts: 521
Default

Ive been working on my physics homework for the last couple hours and Ive got all but one problem. Im not even sure really where to start. I know its a conservation of momentum problem, but its got both translational and rotational momentum in it. If anyone knows how to relate the 2, I'd be eternally grateful.



Thnx

Andy



Heres the problem:
CGeek2k is offline  
Old 04-17-2004, 11:00 PM
  #2  
Senior Member
 
CrashFactory's Avatar
 
Join Date: Dec 2002
Location: Cowgill , Missouri
Posts: 370
Default

Sorry I don't speak greek...
CrashFactory is offline  
Old 04-17-2004, 11:01 PM
  #3  
Senior Member
Thread Starter
 
CGeek2k's Avatar
 
Join Date: Nov 2003
Location: Hell (Colorado School of Mines)
Posts: 521
Default

Its not greek, its geek.
CGeek2k is offline  
Old 04-18-2004, 12:38 AM
  #4  
Senior Member
 
ROTARYROCKET7's Avatar
 
Join Date: Dec 2002
Location: QUEENS NYC
Posts: 1,687
Default

Originally Posted by CGeek2k' date='Apr 17 2004, 08:01 PM
Its not greek, its geek.
icould solve it but i dont want to bore myself with old skool physics sowwy
ROTARYROCKET7 is offline  
Old 04-18-2004, 01:11 AM
  #5  
Senior Member
Thread Starter
 
CGeek2k's Avatar
 
Join Date: Nov 2003
Location: Hell (Colorado School of Mines)
Posts: 521
Default

All Im asking for is one equation relating angular momentum to translational momentum. If, that is, you even know it.
CGeek2k is offline  
Old 04-18-2004, 02:00 AM
  #6  
Junior Member
 
Striker's Avatar
 
Join Date: Oct 2002
Location: calgary
Posts: 28
Default

okay, translational momentum is p = mv. figure out how much momentum is transferred because of the angle. input in the angular momentum formula, L = Iw (w = v/r) the w symbol is the curved w, i believe it's called omega. inertia for a rod is 1/12 (mass)(length)^2 so we get angular momentum = (Mass x length^2 x velocity) / (12 x radius)



i hope this helps.
Striker is offline  
Old 04-18-2004, 05:16 AM
  #7  
Senior Member
 
CrashFactory's Avatar
 
Join Date: Dec 2002
Location: Cowgill , Missouri
Posts: 370
Cool

sounds greek to me :P



Sean
CrashFactory is offline  
Old 04-18-2004, 12:01 PM
  #8  
Senior Member
Thread Starter
 
CGeek2k's Avatar
 
Join Date: Nov 2003
Location: Hell (Colorado School of Mines)
Posts: 521
Default

The way Im reading that, it will give me the angular velocity of the stick if all of the impulse from the puck goes into angular momentum. This doesnt work as the stick has angular and translational momentum. I can use that to get the tangential velocity at the point of impact, but how do I find out how much of the velocity goes into rotation and how much goes into translation?



I have been able to solve for the angular velocity gained by the stick by using L=R X(cross) V. Using this I can find the 'angular' momentum of the puck before and after the collision as related to the center of mass of the stick. However using this I can only solve for angular velocity of the stick. If I try to solve the equation for the velocity vector of the center of mass, then 'R' is zero and I have no velocity. I have tried to put these answers in (the problems are online) but the damn thing just keeps telling me Im wrong.
CGeek2k is offline  
Old 04-18-2004, 12:19 PM
  #9  
Junior Member
 
Striker's Avatar
 
Join Date: Oct 2002
Location: calgary
Posts: 28
Default

hmmm, i thought it was attached at the bottom. i never figured out how to do these questions. sorry man.
Striker is offline  
Related Topics
Thread
Thread Starter
Forum
Replies
Last Post
fcrotornut
2nd Generation Specific
27
04-18-2007 04:31 PM
WKZ (Works)
Race Prep
2
12-16-2004 07:04 AM
CGeek2k
Insert BS here
15
02-14-2004 07:42 AM
ROTARYROCKET7
Insert BS here
16
10-13-2003 04:07 PM
up&coming
2nd Generation Specific
7
10-07-2003 09:17 PM

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 


Quick Reply: Physics Help



All times are GMT -5. The time now is 11:10 PM.