Some Brain teasers for you guys
Thread Starter
Senior Member
Joined: Dec 2001
Posts: 689
I just thought I'd throw these out and see if anyone can figure out the answers.
#1
A salesman is away from home on business. Unfortunately, he has lost his wallet, but still needs to pay for a week's stay at a hotel. The hotel he is staying at charges $100 a night. The only item of value he has on him is a 7 link gold chain, each link being worth $100. By only making two cuts in the chain how can he pay for his hotel room EACH night of his stay using only the gold chain.
#2
Identify the pattern and repeat
O
T
T
F
F
S
S
E
N
T
Good Luck!
I'll post the answers later.
#1
A salesman is away from home on business. Unfortunately, he has lost his wallet, but still needs to pay for a week's stay at a hotel. The hotel he is staying at charges $100 a night. The only item of value he has on him is a 7 link gold chain, each link being worth $100. By only making two cuts in the chain how can he pay for his hotel room EACH night of his stay using only the gold chain.
#2
Identify the pattern and repeat
O
T
T
F
F
S
S
E
N
T
Good Luck!
I'll post the answers later.
omghi2u
Joined: Mar 2002
Posts: 7,259
From: Los Angeles, CA
not even gonna try, im confused just reading it.
but the first one y not cut the face off (two cuts) and have the 7 links together to pay for seven nights. i guess i just tried so ignore my first statement because im too lazy to delete it
but the first one y not cut the face off (two cuts) and have the 7 links together to pay for seven nights. i guess i just tried so ignore my first statement because im too lazy to delete it
Senior Member
Joined: Nov 2001
Posts: 7,316
From: Bay Area, CA
If the chain is arranged like this:
OOOOOOO
with the links being numbered 1 through 7 from left to right, you can cut at the joint between 2 and 3, which will make a cut in each link with 1 cut. You can do the same for the joint bewtween 5 and 6. Technically that's 4 cuts, but you're only actually cutting twice.
I'll take a look at the second one and get back to you.
OOOOOOO
with the links being numbered 1 through 7 from left to right, you can cut at the joint between 2 and 3, which will make a cut in each link with 1 cut. You can do the same for the joint bewtween 5 and 6. Technically that's 4 cuts, but you're only actually cutting twice.
I'll take a look at the second one and get back to you.
Senior Member
Joined: Nov 2001
Posts: 888
From: South Jersey
Originally Posted by Turbo II' date='Aug 16 2002, 02:54 AM
[quote name='rotarychainsaw' date='Aug 15 2002, 07:31 PM']number two 
ne two three etc...
ne two three etc...i think i'm halfway there. whats to repeat?
Senior Member
Joined: Nov 2001
Posts: 7,316
From: Bay Area, CA
Originally Posted by rotarychainsaw' date='Aug 15 2002, 07:13 PM
[quote name='Turbo II' date='Aug 16 2002, 02:54 AM'][quote name='rotarychainsaw' date='Aug 15 2002, 07:31 PM']number two ne two three etc...
ne two three etc...i think i'm halfway there. whats to repeat?[/quote]
You can only make two cuts to separate the chain into 7 individual links.
Senior Member
Joined: Nov 2001
Posts: 7,316
From: Bay Area, CA
Ok, I just looked at the 2nd one on paper, and I think I figured it out:
If I assign each letter of the alphabet a number from 1-26 starting with A and going alphabetically to Z then I get a pattern that looks like this:
15 20 20 6
6 19 19 5
14 20
If you extend that you get:
14 20 20 5 -->N T T E
5 19 19 13 -->E S S M
13 20 20 4 -->M T T D
etc.
How's that?
If I assign each letter of the alphabet a number from 1-26 starting with A and going alphabetically to Z then I get a pattern that looks like this:
15 20 20 6
6 19 19 5
14 20
If you extend that you get:
14 20 20 5 -->N T T E
5 19 19 13 -->E S S M
13 20 20 4 -->M T T D
etc.
How's that?
Senior Member
Joined: Nov 2001
Posts: 7,316
From: Bay Area, CA
Originally Posted by 13BAce' date='Aug 15 2002, 07:40 PM
Ok, I just looked at the 2nd one on paper, and I think I figured it out:
If I assign each letter of the alphabet a number from 1-26 starting with A and going alphabetically to Z then I get a pattern that looks like this:
15 20 20 6
6 19 19 5
14 20
If you extend that you get:
14 20 20 5 -->N T T E
5 19 19 13 -->E S S M
13 20 20 4 -->M T T D
etc.
How's that?
If I assign each letter of the alphabet a number from 1-26 starting with A and going alphabetically to Z then I get a pattern that looks like this:
15 20 20 6
6 19 19 5
14 20
If you extend that you get:
14 20 20 5 -->N T T E
5 19 19 13 -->E S S M
13 20 20 4 -->M T T D
etc.
How's that?
O N M L K
T T T T T
T T T T T
F -> E-> D-> C-> B
F E D C B
S S S S S
S S S S S
E D C B A
So we're going 1 letter lower in the 1st, 4th, 5th, and 8th positions.
omghi2u
Joined: Mar 2002
Posts: 7,259
From: Los Angeles, CA
Originally Posted by 13BAce' date='Aug 15 2002, 09:45 PM
[quote name='13BAce' date='Aug 15 2002, 07:40 PM']Ok, I just looked at the 2nd one on paper, and I think I figured it out:
If I assign each letter of the alphabet a number from 1-26 starting with A and going alphabetically to Z then I get a pattern that looks like this:
15 20 20 6
6 19 19 5
14 20
If you extend that you get:
14 20 20 5 -->N T T E
5 19 19 13 -->E S S M
13 20 20 4 -->M T T D
etc.
How's that?
If I assign each letter of the alphabet a number from 1-26 starting with A and going alphabetically to Z then I get a pattern that looks like this:
15 20 20 6
6 19 19 5
14 20
If you extend that you get:
14 20 20 5 -->N T T E
5 19 19 13 -->E S S M
13 20 20 4 -->M T T D
etc.
How's that?
O N M L K
T T T T T
T T T T T
F -> E-> D-> C-> B
F E D C B
S S S S S
S S S S S
E D C B A
So we're going 1 letter lower in the 1st, 4th, 5th, and 8th positions.[/quote]
still dont get it ace.