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Okay, I have one math problem left on my quiz that I can't figure out. The sum of three consecutive odd integers is the same as the smallest of these integers. Find the smallest of these integers and find the greatest of these integers. __________Smallest ___________Greatest it doesn't make sense to me, because how can you add numbers to a smaller number, and get the smaller number for your answer? |
What the hell is an integers. https://www.nopistons.com/forums/pub...1047683561.gif
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Originally Posted by TyresmokinRx7' date='Jun 23 2003, 11:04 AM
What the hell is an integers. https://www.nopistons.com/forums/pub...1047683561.gif
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negative
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Originally Posted by rfreeman27' date='Jun 23 2003, 11:16 AM
negative
I think they may have screwed up writing the problem or something...unless someone has an answer that I can't seem to find |
easy
-3 -1 1 -3 + -1 = -4 -4 + 1 = -3 The sum of three consecutive odd integers is the same as the smallest of these integers. Find the smallest of these integers and find the greatest of these integers. -3 Smallest 1 Greatest |
AN interger is non negative because it lies in the set of real numbers. If you go into negative numbers with intergers you are now entering the set of imaginary numbers. Those problems are brain teasers and the way to solve it by trial and error using odd and even numbers. I just failed my math test for Differential Equations.
SOlve this problem: x^2 means x squared okay.. y' means first derivative.. '' means second and so on e= eulers equation = 2.7 ln= natural log cos t^2 + sin t^2 =1 ( identity) cot = cotangent sec= secant IIGht Find a Particular Solution for y'' + 4y= 3 csc t ( csc is the cosecant so its 1/sin (t) ) SO the general solution is yc(t) = C1 cos 2t + C2 sin2t The general solution is off this form because the discriminat b2-4ac ( part of the quadratic equation of the form -b +- (b2-4ac)^(1/2) / 2(a) ). is less than 0. so then the general equation is y= e ^ lambda (t) ( c1 cos u(t) + c2 sin u(t) ) and the discrimant therfore gives us lambda = 0 so e raised to the zero is 1 and then we get C1 cos 2t + C2 sin2t. Find the coefficiants c1 and c2 byusing variation of parameters where the first condition that needs to be satisfied is 1) v1'y1 + v2'y2= 0 2) v1'y1' + v2'y2' = csc (t) by using trigonometric substituition. Engineers of NP.com gimme this answer! The answer is y= 3 sint + 3/2 ln | csc t - cot t|sin2t + c1 cos2t + c2 sin2t |
rigggggghhhhhhhhhhhhhhhttt
but an integer is still negative, unless they say a real number...then its not negative |
math = teh suxx0rz
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integer <mathematics> (Or "whole number") One of the finite numbers in the infinite set ..., -3, -2, -1, 0, 1, 2, 3, ... |
Originally Posted by ROTARYROCKET7' date='Jun 23 2003, 08:00 AM
AN interger is non negative because it lies in the set of real numbers. If you go into negative numbers with intergers you are now entering the set of imaginary numbers. Those problems are brain teasers and the way to solve it by trial and error using odd and even numbers. I just failed my math test for Differential Equations.
SOlve this problem: x^2 means x squared okay.. y' means first derivative.. '' means second and so on e= eulers equation = 2.7 ln= natural log cos t^2 + sin t^2 =1 ( identity) cot = cotangent sec= secant IIGht Find a Particular Solution for y'' + 4y= 3 csc t ( csc is the cosecant so its 1/sin (t) ) SO the general solution is yc(t) = C1 cos 2t + C2 sin2t The general solution is off this form because the discriminat b2-4ac ( part of the quadratic equation of the form -b +- (b2-4ac)^(1/2) / 2(a) ). is less than 0. so then the general equation is y= e ^ lambda (t) ( c1 cos u(t) + c2 sin u(t) ) and the discrimant therfore gives us lambda = 0 so e raised to the zero is 1 and then we get C1 cos 2t + C2 sin2t. Find the coefficiants c1 and c2 byusing variation of parameters where the first condition that needs to be satisfied is 1) v1'y1 + v2'y2= 0 2) v1'y1' + v2'y2' = csc (t) by using trigonometric substituition. Engineers of NP.com gimme this answer! The answer is y= 3 sint + 3/2 ln | csc t - cot t|sin2t + c1 cos2t + c2 sin2t The only reason I would find that intresting, is if it made my 7 go faster. I supose, were all different https://www.nopistons.com/forums/pub...IR#>/smile.png |
i feel like locking this thread, math = the not gooder
mike |
Originally Posted by ROTARYROCKET7' date='Jun 23 2003, 08:00 AM
AN interger is non negative because it lies in the set of real numbers. If you go into negative numbers with intergers you are now entering the set of imaginary numbers. Those problems are brain teasers and the way to solve it by trial and error using odd and even numbers. I just failed my math test for Differential Equations.
SOlve this problem: x^2 means x squared okay.. y' means first derivative.. '' means second and so on e= eulers equation = 2.7 ln= natural log cos t^2 + sin t^2 =1 ( identity) cot = cotangent sec= secant IIGht Find a Particular Solution for y'' + 4y= 3 csc t ( csc is the cosecant so its 1/sin (t) ) SO the general solution is yc(t) = C1 cos 2t + C2 sin2t The general solution is off this form because the discriminat b2-4ac ( part of the quadratic equation of the form -b +- (b2-4ac)^(1/2) / 2(a) ). is less than 0. so then the general equation is y= e ^ lambda (t) ( c1 cos u(t) + c2 sin u(t) ) and the discrimant therfore gives us lambda = 0 so e raised to the zero is 1 and then we get C1 cos 2t + C2 sin2t. Find the coefficiants c1 and c2 byusing variation of parameters where the first condition that needs to be satisfied is 1) v1'y1 + v2'y2= 0 2) v1'y1' + v2'y2' = csc (t) by using trigonometric substituition. Engineers of NP.com gimme this answer! The answer is y= 3 sint + 3/2 ln | csc t - cot t|sin2t + c1 cos2t + c2 sin2t |
Originally Posted by djgiantrobot' date='Jun 23 2003, 12:21 PM
[quote name='ROTARYROCKET7' date='Jun 23 2003, 08:00 AM'] AN interger is non negative because it lies in the set of real numbers. If you go into negative numbers with intergers you are now entering the set of imaginary numbers. Those problems are brain teasers and the way to solve it by trial and error using odd and even numbers. I just failed my math test for Differential Equations.
SOlve this problem: x^2 means x squared okay.. y' means first derivative.. '' means second and so on e= eulers equation = 2.7 ln= natural log cos t^2 + sin t^2 =1 ( identity) cot = cotangent sec= secant IIGht Find a Particular Solution for y'' + 4y= 3 csc t ( csc is the cosecant so its 1/sin (t) ) SO the general solution is yc(t) = C1 cos 2t + C2 sin2t The general solution is off this form because the discriminat b2-4ac ( part of the quadratic equation of the form -b +- (b2-4ac)^(1/2) / 2(a) ). is less than 0. so then the general equation is y= e ^ lambda (t) ( c1 cos u(t) + c2 sin u(t) ) and the discrimant therfore gives us lambda = 0 so e raised to the zero is 1 and then we get C1 cos 2t + C2 sin2t. Find the coefficiants c1 and c2 byusing variation of parameters where the first condition that needs to be satisfied is 1) v1'y1 + v2'y2= 0 2) v1'y1' + v2'y2' = csc (t) by using trigonometric substituition. Engineers of NP.com gimme this answer! The answer is y= 3 sint + 3/2 ln | csc t - cot t|sin2t + c1 cos2t + c2 sin2t School ended like a week or two ago or soemthing, i couldnt tell you a damn thing about algebra now.. https://www.nopistons.com/forums/pub...1047683329.gif |
Originally Posted by djgiantrobot' date='Jun 23 2003, 08:21 AM
About a year ago i would have actually tried to help you with that, you'd be shocked how quick you'll loose all that once you are out of school. oh yeah, someone hire me.
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I believe the answer is -3, -1, and 1. Thanks!
(someone else also came up with this answer, so 2 alike answers are good enough for me!) |
The orginal problem is impossible to solve with only WHOLE numbers. Integers include all REAL numbers, Their NEGATIVES, and zeros.
Oh and RotaryRocket7 is wrong about Imaginary numbers. Those are the Square root of Negative numbers. All this **** was on my Nuke exam for the NAVY. Apperently they want people to know math while working on Nuclear reactors. Go figure https://www.nopistons.com/forums/pub...1047683561.gif |
Originally Posted by Joe Flo' date='Jun 23 2003, 01:32 PM
The orginal problem is impossible to solve with only WHOLE numbers. Integers include all REAL numbers, Their NEGATIVES, and zeros.
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Originally Posted by Baldy' date='Jun 23 2003, 09:37 AM
[quote name='Joe Flo' date='Jun 23 2003, 01:32 PM'] The orginal problem is impossible to solve with only WHOLE numbers. Integers include all REAL numbers, Their NEGATIVES, and zeros.
Yes but you know what I mean.... I forgot what all positive numbers where called. I left my brain in High School |
I say school has been out way to long to be doin god damn math. Hell there is only like 3 fields where you will ever use that ****. I stay stick with car math
Me + RX-7 = https://www.nopistons.com/forums/pub...#>/biggrin.png https://www.nopistons.com/forums/pub...1047683473.gif https://www.nopistons.com/forums/pub...1047683329.gif |
Originally Posted by Joe Flo' date='Jun 23 2003, 01:39 PM
[quote name='Baldy' date='Jun 23 2003, 09:37 AM'] [quote name='Joe Flo' date='Jun 23 2003, 01:32 PM'] The orginal problem is impossible to solve with only WHOLE numbers. Integers include all REAL numbers, Their NEGATIVES, and zeros.
Yes but you know what I mean.... I forgot what all positive numbers where called. I left my brain in High School [/quote] I suppose I do |
Originally Posted by =RX-7 KID=-' date='Jun 23 2003, 01:40 PM
I say school has been out way to long to be doin god damn math. Hell there is only like 3 fields where you will ever use that ****. I stay stick with car math
Me + RX-7 = https://www.nopistons.com/forums/pub...#>/biggrin.png https://www.nopistons.com/forums/pub...1047683473.gif https://www.nopistons.com/forums/pub...1047683329.gif This problem was for a quiz my step mom has. She's like 39 (or somewhere around there). She's back in school to get a degree, and earn more money (not like she doesn't make enough already). My good friend's dad works for the city, and after years of experience, is now some sort of traffic engineer. But he's hit a pay ceiling, because he never got a degree. You don't necessarily need math, all you need is that damn piece of paper. |
i thought all negative numbers werent "REAL numbers"....seeing as you cannot have a negative amount of something, its just not there..
"how many turbos you have in that NA 13B?" "negative 1?" "how much did you steal that 3-rotor for" "negative 3500?" |
Originally Posted by =RX-7 KID=-' date='Jun 23 2003, 09:40 AM
I say school has been out way to long to be doin god damn math. Hell there is only like 3 fields where you will ever use that ****. I stay stick with car math
Me + RX-7 = https://www.nopistons.com/forums/pub...#>/biggrin.png https://www.nopistons.com/forums/pub...1047683473.gif https://www.nopistons.com/forums/pub...1047683329.gif |
Originally Posted by FrestyleReaction' date='Jun 23 2003, 02:08 PM
i thought all negative numbers werent "REAL numbers"....seeing as you cannot have a negative amount of something, its just not there..
"how many turbos you have in that NA 13B?" "negative 1?" "how much did you steal that 3-rotor for" "negative 3500?" oh, and you can buy something for negative dollars. Like if I got a hat from you, and paid -$5, that means I got your hat, and you paid me $5. |
Originally Posted by FrestyleReaction' date='Jun 23 2003, 10:08 AM
"how many turbos you have in that NA 13B?"
"negative 1?" "how much did you steal that 3-rotor for" "negative 3500?" |
Originally Posted by FrestyleReaction' date='Jun 23 2003, 10:08 AM
"how many turbos you have in that NA 13B?"
"negative 1?" mike |
Originally Posted by j9fd3s' date='Jun 23 2003, 11:18 AM
[quote name='FrestyleReaction' date='Jun 23 2003, 10:08 AM']
"how many turbos you have in that NA 13B?" "negative 1?" mike [/quote] https://www.nopistons.com/forums/pub...1047683785.gif Good one. |
Originally Posted by j9fd3s' date='Jun 23 2003, 02:18 PM
[quote name='FrestyleReaction' date='Jun 23 2003, 10:08 AM']
"how many turbos you have in that NA 13B?" "negative 1?" mike [/quote] then you would have a turbo in the trunk and if you bought a hat for -5 .... then you would still be paying 0 dollars...meaning that you bought a hat for 0 dollars and i gave you 5 bucks |
Originally Posted by FrestyleReaction' date='Jun 23 2003, 04:08 PM
[quote name='j9fd3s' date='Jun 23 2003, 02:18 PM'] [quote name='FrestyleReaction' date='Jun 23 2003, 10:08 AM']
"how many turbos you have in that NA 13B?" "negative 1?" mike [/quote] then you would have a turbo in the trunk and if you bought a hat for -5 .... then you would still be paying 0 dollars...meaning that you bought a hat for 0 dollars and i gave you 5 bucks [/quote] Interpretation my friend, that's the only difference there. |
Originally Posted by WishIhadaRX7' date='Jun 23 2003, 03:21 PM
[quote name='FrestyleReaction' date='Jun 23 2003, 04:08 PM'] [quote name='j9fd3s' date='Jun 23 2003, 02:18 PM'] [quote name='FrestyleReaction' date='Jun 23 2003, 10:08 AM']
"how many turbos you have in that NA 13B?" "negative 1?" mike [/quote] then you would have a turbo in the trunk and if you bought a hat for -5 .... then you would still be paying 0 dollars...meaning that you bought a hat for 0 dollars and i gave you 5 bucks [/quote] Interpretation my friend, that's the only difference there. [/quote] o_O i dont get it |
so you're gonna give me $5 and a hat?
mike |
Oh crap! not enough brain power to drive nome now..
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Originally Posted by 75 Repu' date='Jun 23 2003, 02:29 PM
Oh crap! not enough brain power to drive nome now..
mike |
M..u..s..t......r..e...s..t.........
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lets get the number systems straight.
Real Number system includes: Whole numbers(all positive whole numbers), natural(postive whole's, including 0), integers(postive/negative whole numbers), rational(all fractional numbers), irrational(non terminating, non repeating numbers like pi) i am sure of all facts except for which zero belongs too; natural or whole. |
i didnt read every reply in here, and im not a math god or anything, but after two years of computer programming i know what an integer is for sure. Integers can be either negative or positive, but are only whole numbers.
Not integers: 1.5 150.6 67.8 .88 Integers: 1 45 345 -6 -23 -456 Integers are infinite less yer doing C++ than its only up to 32,767 (without long). Jus my two cents, not worth much. |
I can see who passed math class and who didn't
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OUCH!.. make it stop.
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i passed math fine.
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