j9fd3s

thats enough to do like 3-4 hundred hp!



mike

UniqueTII

pi*id^2*h where id is the internal diameter of the hose. That's insane.



~800 in^3 just for the tubing. That's over 3 gallons.



I'm hoping there's something wrong with my math, because that's crazy!

Baldy

the tube alone is something like 235.6 in^3, if I did that right. Which, I think, is something like .14 ft^3

vosko

that is alot of flow there!

Baldy

I think it's pi, times r^2 (radius squared). The radius would be 1.25; squared is 1.5625. And height is 48 (4' x 12"), so:



pi x 1.5625 (in^2) x 48 in.= ~235.5 in^3



to ft^3, 12 x 12 x 12=1,728

235.5 / 1,728 = ~0.14



is that right? it's been awhile since math

rx7machine

Looks nice. Used it yet?

kkw4p

Had I known that I was actually going to use the material we were being tought, I would've paid more attention in hydrology lab. Yeah.. so this is an example of calculating beef flow.. but it's still at least applied!

TyresmokinRx7

You must be thirsty.

Baldy

ever see that guy on tv that did a reverse stomach pump? He basically just swallowed/shoved a tube down to his stomach, and had a large pump/syringe type thing, and he could just pump in our out whatever liquid he wanted. You should figure out how to do that!!



Just imagine the possibilities!!

Srce

LMFAO, I was gonna point that out.